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Fixed #105 - Opening explorer on a filename with a space in it failed.

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daid 2012-05-15 13:18:38 +02:00
parent e22694bfda
commit 3ea2960d88
1 changed files with 1 additions and 1 deletions
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2
Cura/util/exporer.py
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@ -15,7 +15,7 @@ def hasExporer():
def openExporer(filename):
if sys.platform == 'win32' or sys.platform == 'cygwin':
subprocess.Popen(['explorer', "/select,%s" % (filename)])
subprocess.Popen(r'explorer /select,"%s"' % (filename))
if sys.platform == 'darwin':
subprocess.Popen(['open', os.path.split(filename)[0]])
if sys.platform == 'linux2':